21=18(z+1)-6(3z-9)

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Solution for 21=18(z+1)-6(3z-9) equation: 



21=18(z+1)-6(3z-9)

We move all terms to the left:

21-(18(z+1)-6(3z-9))=0



We calculate terms in parentheses: -(18(z+1)-6(3z-9)), so:

18(z+1)-6(3z-9)

We multiply parentheses

18z-18z+18+54

We add all the numbers together, and all the variables

72

Back to the equation:

-(72)



We add all the numbers together, and all the variables

-51!=0

There is no solution for this equation

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