21=-3(23-m)+3(m-2)

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Solution for 21=-3(23-m)+3(m-2) equation: 



21=-3(23-m)+3(m-2)

We move all terms to the left:

21-(-3(23-m)+3(m-2))=0

We add all the numbers together, and all the variables

-(-3(-1m+23)+3(m-2))+21=0



We calculate terms in parentheses: -(-3(-1m+23)+3(m-2)), so:

-3(-1m+23)+3(m-2)

We multiply parentheses

3m+3m-69-6

We add all the numbers together, and all the variables

6m-75

Back to the equation:

-(6m-75)



We get rid of parentheses

-6m+75+21=0

We add all the numbers together, and all the variables

-6m+96=0

We move all terms containing m to the left, all other terms to the right

-6m=-96

m=-96/-6

m=+16

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