21/3x+10=40-22/3x

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Solution for 21/3x+10=40-22/3x equation: 



21/3x+10=40-22/3x

We move all terms to the left:

21/3x+10-(40-22/3x)=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R





Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

21/3x-(-22/3x+40)+10=0

We get rid of parentheses

21/3x+22/3x-40+10=0

We multiply all the terms by the denominator


-40*3x+10*3x+21+22=0

We add all the numbers together, and all the variables

-40*3x+10*3x+43=0

Wy multiply elements

-120x+30x+43=0

We add all the numbers together, and all the variables

-90x+43=0

We move all terms containing x to the left, all other terms to the right

-90x=-43

x=-43/-90

x=43/90

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