21/2(6-4x)+3x=-6(x-5)

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Solution for 21/2(6-4x)+3x=-6(x-5) equation: 



21/2(6-4x)+3x=-6(x-5)

We move all terms to the left:

21/2(6-4x)+3x-(-6(x-5))=0



Domain of the equation: 2(6-4x)!=0

x∈R



We add all the numbers together, and all the variables

21/2(-4x+6)+3x-(-6(x-5))=0

We add all the numbers together, and all the variables

3x+21/2(-4x+6)-(-6(x-5))=0

We multiply all the terms by the denominator


3x*2(-4x+6)-((-6(x-5)))*2(-4x+6)+21=0



We calculate terms in parentheses: -((-6(x-5)))*2(-4x+6), so:

(-6(x-5)))*2(-4x+6

We add all the numbers together, and all the variables

-4x+(-6(x-5)))*2(+6

Back to the equation:

-(-4x+(-6(x-5)))*2(+6)



We add all the numbers together, and all the variables

3x*2(-4x+6)-(-4x+(-6(x-5)))*26+21=0

Wy multiply elements

6x^2(--(-4x+(-6(x-5)))*26+21=0

We use the square of the difference formula

6x^2(+(-4x+(-6(x-5)))*26+21=0

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