21+r=3(r+4)+7

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Solution for 21+r=3(r+4)+7 equation: 



21+r=3(r+4)+7

We move all terms to the left:

21+r-(3(r+4)+7)=0



We calculate terms in parentheses: -(3(r+4)+7), so:

3(r+4)+7

We multiply parentheses

3r+12+7

We add all the numbers together, and all the variables

3r+19

Back to the equation:

-(3r+19)



We get rid of parentheses

r-3r-19+21=0

We add all the numbers together, and all the variables

-2r+2=0

We move all terms containing r to the left, all other terms to the right

-2r=-2

r=-2/-2

r=1

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