21+3x=1/2x+3

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Solution for 21+3x=1/2x+3 equation:



21+3x=1/2x+3
We move all terms to the left:
21+3x-(1/2x+3)=0
Domain of the equation: 2x+3)!=0
x∈R
We get rid of parentheses
3x-1/2x-3+21=0
We multiply all the terms by the denominator
3x*2x-3*2x+21*2x-1=0
Wy multiply elements
6x^2-6x+42x-1=0
We add all the numbers together, and all the variables
6x^2+36x-1=0
a = 6; b = 36; c = -1;
Δ = b2-4ac
Δ = 362-4·6·(-1)
Δ = 1320
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{1320}=\sqrt{4*330}=\sqrt{4}*\sqrt{330}=2\sqrt{330}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-2\sqrt{330}}{2*6}=\frac{-36-2\sqrt{330}}{12} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+2\sqrt{330}}{2*6}=\frac{-36+2\sqrt{330}}{12} $

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