21+3(k-4)=2(k+5)-k

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Solution for 21+3(k-4)=2(k+5)-k equation:


Simplifying
21 + 3(k + -4) = 2(k + 5) + -1k

Reorder the terms:
21 + 3(-4 + k) = 2(k + 5) + -1k
21 + (-4 * 3 + k * 3) = 2(k + 5) + -1k
21 + (-12 + 3k) = 2(k + 5) + -1k

Combine like terms: 21 + -12 = 9
9 + 3k = 2(k + 5) + -1k

Reorder the terms:
9 + 3k = 2(5 + k) + -1k
9 + 3k = (5 * 2 + k * 2) + -1k
9 + 3k = (10 + 2k) + -1k

Combine like terms: 2k + -1k = 1k
9 + 3k = 10 + 1k

Solving
9 + 3k = 10 + 1k

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '-1k' to each side of the equation.
9 + 3k + -1k = 10 + 1k + -1k

Combine like terms: 3k + -1k = 2k
9 + 2k = 10 + 1k + -1k

Combine like terms: 1k + -1k = 0
9 + 2k = 10 + 0
9 + 2k = 10

Add '-9' to each side of the equation.
9 + -9 + 2k = 10 + -9

Combine like terms: 9 + -9 = 0
0 + 2k = 10 + -9
2k = 10 + -9

Combine like terms: 10 + -9 = 1
2k = 1

Divide each side by '2'.
k = 0.5

Simplifying
k = 0.5

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