21(x+4)-78=3(7x+2)

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Solution for 21(x+4)-78=3(7x+2) equation: 



21(x+4)-78=3(7x+2)

We move all terms to the left:

21(x+4)-78-(3(7x+2))=0

We multiply parentheses

21x-(3(7x+2))+84-78=0



We calculate terms in parentheses: -(3(7x+2)), so:

3(7x+2)

We multiply parentheses

21x+6

Back to the equation:

-(21x+6)



We add all the numbers together, and all the variables

21x-(21x+6)+6=0

We get rid of parentheses

21x-21x-6+6=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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