21(n=4)+21n=10n(n-4)

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Solution for 21(n=4)+21n=10n(n-4) equation: 



21(n=4)+21n=10n(n-4)

We move all terms to the left:

21(n-(4)+21n)=0

We add all the numbers together, and all the variables

21(22n-4)=0

We multiply parentheses

462n-84=0

We move all terms containing n to the left, all other terms to the right

462n=84

n=84/462

n=2/11

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