20z-12=4(4z+3)

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Solution for 20z-12=4(4z+3) equation:


20z-12=4(4z+3)

We simplify the equation to the form, which is simple to understand 
20z-12=4(4z+3)

Reorder the terms in parentheses
20z-12=+(+16z+12)

Remove unnecessary parentheses
+20z-12=+16z+12

We move all terms containing z to the left and all other terms to the right. 
+20z-16z=+12+12

We simplify left and right side of the equation. 
+4z=+24

We divide both sides of the equation by 4 to get z. 
z=6

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