20z(2z+5)=-40

Solution for 20z(2z+5)=-40 equation:

Simplifying
20z(2z + 5) = -40

Reorder the terms:
20z(5 + 2z) = -40
(5 * 20z + 2z * 20z) = -40
(100z + 40z2) = -40

Solving
100z + 40z2 = -40

Solving for variable 'z'.

Reorder the terms:
40 + 100z + 40z2 = -40 + 40

Combine like terms: -40 + 40 = 0
40 + 100z + 40z2 = 0

Factor out the Greatest Common Factor (GCF), '20'.
20(2 + 5z + 2z2) = 0

Factor a trinomial.
20((2 + z)(1 + 2z)) = 0

Ignore the factor 20.
Subproblem 1
Set the factor '(2 + z)' equal to zero and attempt to solve:

Simplifying
2 + z = 0

Solving
2 + z = 0

Move all terms containing z to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + z = 0 + -2

Combine like terms: 2 + -2 = 0
0 + z = 0 + -2
z = 0 + -2

Combine like terms: 0 + -2 = -2
z = -2

Simplifying
z = -2
Subproblem 2
Set the factor '(1 + 2z)' equal to zero and attempt to solve:

Simplifying
1 + 2z = 0

Solving
1 + 2z = 0

Move all terms containing z to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 2z = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 2z = 0 + -1
2z = 0 + -1

Combine like terms: 0 + -1 = -1
2z = -1

Divide each side by '2'.
z = -0.5

Simplifying
z = -0.5
Solution
z = {-2, -0.5}