20y-y2=96

Solution for 20y-y2=96 equation:

20y-y2=96

We move all terms to the left:

20y-y2-(96)=0

We add all the numbers together, and all the variables

-1y^2+20y-96=0

a = -1; b = 20; c = -96;
Δ = b2-4ac
Δ = 202-4·(-1)·(-96)
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-4}{2*-1}=\frac{-24}{-2}
=+12
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+4}{2*-1}=\frac{-16}{-2}
=+8
$