20y-5(1+y)=5(4y-4)-40

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Solution for 20y-5(1+y)=5(4y-4)-40 equation:


Simplifying
20y + -5(1 + y) = 5(4y + -4) + -40
20y + (1 * -5 + y * -5) = 5(4y + -4) + -40
20y + (-5 + -5y) = 5(4y + -4) + -40

Reorder the terms:
-5 + 20y + -5y = 5(4y + -4) + -40

Combine like terms: 20y + -5y = 15y
-5 + 15y = 5(4y + -4) + -40

Reorder the terms:
-5 + 15y = 5(-4 + 4y) + -40
-5 + 15y = (-4 * 5 + 4y * 5) + -40
-5 + 15y = (-20 + 20y) + -40

Reorder the terms:
-5 + 15y = -20 + -40 + 20y

Combine like terms: -20 + -40 = -60
-5 + 15y = -60 + 20y

Solving
-5 + 15y = -60 + 20y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-20y' to each side of the equation.
-5 + 15y + -20y = -60 + 20y + -20y

Combine like terms: 15y + -20y = -5y
-5 + -5y = -60 + 20y + -20y

Combine like terms: 20y + -20y = 0
-5 + -5y = -60 + 0
-5 + -5y = -60

Add '5' to each side of the equation.
-5 + 5 + -5y = -60 + 5

Combine like terms: -5 + 5 = 0
0 + -5y = -60 + 5
-5y = -60 + 5

Combine like terms: -60 + 5 = -55
-5y = -55

Divide each side by '-5'.
y = 11

Simplifying
y = 11

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