20x2-95x=5

Solution for 20x2-95x=5 equation:

20x^2-95x=5

We move all terms to the left:

20x^2-95x-(5)=0

a = 20; b = -95; c = -5;
Δ = b2-4ac
Δ = -952-4·20·(-5)
Δ = 9425
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9425}=\sqrt{25*377}=\sqrt{25}*\sqrt{377}=5\sqrt{377}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-95)-5\sqrt{377}}{2*20}=\frac{95-5\sqrt{377}}{40}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-95)+5\sqrt{377}}{2*20}=\frac{95+5\sqrt{377}}{40}
$