20x2-6x-73=0

Solution for 20x2-6x-73=0 equation:

20x^2-6x-73=0

a = 20; b = -6; c = -73;
Δ = b2-4ac
Δ = -62-4·20·(-73)
Δ = 5876
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5876}=\sqrt{4*1469}=\sqrt{4}*\sqrt{1469}=2\sqrt{1469}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{1469}}{2*20}=\frac{6-2\sqrt{1469}}{40}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{1469}}{2*20}=\frac{6+2\sqrt{1469}}{40}
$