20x2-40x+20=0

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Solution for 20x2-40x+20=0 equation: 



20x^2-40x+20=0

a = 20; b = -40; c = +20;
Δ = b2-4ac
Δ = -402-4·20·20
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{40}{40}=1$

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