20x2-240x+1=0

Solution for 20x2-240x+1=0 equation:

20x^2-240x+1=0

a = 20; b = -240; c = +1;
Δ = b2-4ac
Δ = -2402-4·20·1
Δ = 57520
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{57520}=\sqrt{16*3595}=\sqrt{16}*\sqrt{3595}=4\sqrt{3595}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-240)-4\sqrt{3595}}{2*20}=\frac{240-4\sqrt{3595}}{40}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-240)+4\sqrt{3595}}{2*20}=\frac{240+4\sqrt{3595}}{40}
$