20x-78=2(2x+41)

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Solution for 20x-78=2(2x+41) equation: 



20x-78=2(2x+41)

We move all terms to the left:

20x-78-(2(2x+41))=0



We calculate terms in parentheses: -(2(2x+41)), so:

2(2x+41)

We multiply parentheses

4x+82

Back to the equation:

-(4x+82)



We get rid of parentheses

20x-4x-82-78=0

We add all the numbers together, and all the variables

16x-160=0

We move all terms containing x to the left, all other terms to the right

16x=160

x=160/16

x=10

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