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20x-10-(5(3x+1)-3(6x-5))-5(6x+1)=0
We multiply parentheses
20x-(5(3x+1)-3(6x-5))-30x-5-10=0
We calculate terms in parentheses: -(5(3x+1)-3(6x-5)), so:We add all the numbers together, and all the variables
5(3x+1)-3(6x-5)
We multiply parentheses
15x-18x+5+15
We add all the numbers together, and all the variables
-3x+20
Back to the equation:
-(-3x+20)
-10x-(-3x+20)-15=0
We get rid of parentheses
-10x+3x-20-15=0
We add all the numbers together, and all the variables
-7x-35=0
We move all terms containing x to the left, all other terms to the right
-7x=35
x=35/-7
x=-5
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