20x+32(21-x)=600

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Solution for 20x+32(21-x)=600 equation: 



20x+32(21-x)=600

We move all terms to the left:

20x+32(21-x)-(600)=0

We add all the numbers together, and all the variables

20x+32(-1x+21)-600=0

We multiply parentheses

20x-32x+672-600=0

We add all the numbers together, and all the variables

-12x+72=0

We move all terms containing x to the left, all other terms to the right

-12x=-72

x=-72/-12

x=+6

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