20x+14=(10x(2))+7+9+(-2)

Solution for 20x+14=(10x(2))+7+9+(-2) equation:

20x+14=(10x(2))+7+9+(-2)

We move all terms to the left:

20x+14-((10x(2))+7+9+(-2))=0

determiningTheFunctionDomain
20x-(10x2+7+9+(-2))+14=0


We calculate terms in parentheses: -(10x2+7+9+(-2)), so:

10x2+7+9+(-2)

We add all the numbers together, and all the variables

10x^2+14

Back to the equation:

-(10x^2+14)


We get rid of parentheses

-10x^2+20x-14+14=0

We add all the numbers together, and all the variables

-10x^2+20x=0

a = -10; b = 20; c = 0;
Δ = b2-4ac
Δ = 202-4·(-10)·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-20}{2*-10}=\frac{-40}{-20}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+20}{2*-10}=\frac{0}{-20}
=0
$