20x+12(x+0.4)=16

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Solution for 20x+12(x+0.4)=16 equation: 



20x+12(x+0.4)=16

We move all terms to the left:

20x+12(x+0.4)-(16)=0

We multiply parentheses

20x+12x+4.8-16=0

We add all the numbers together, and all the variables

32x-11.2=0

We move all terms containing x to the left, all other terms to the right

32x=11.2

x=11.2/32

x=9.3333333333333/26.666666666667

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