20x+10(2x-3)+5(3x-4)+(3x+7)=1059

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Solution for 20x+10(2x-3)+5(3x-4)+(3x+7)=1059 equation: 



20x+10(2x-3)+5(3x-4)+(3x+7)=1059

We move all terms to the left:

20x+10(2x-3)+5(3x-4)+(3x+7)-(1059)=0

We multiply parentheses

20x+20x+15x+(3x+7)-30-20-1059=0

We get rid of parentheses

20x+20x+15x+3x+7-30-20-1059=0

We add all the numbers together, and all the variables

58x-1102=0

We move all terms containing x to the left, all other terms to the right

58x=1102

x=1102/58

x=19

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