20w2=500

Solution for 20w2=500 equation:

20w^2=500

We move all terms to the left:

20w^2-(500)=0

a = 20; b = 0; c = -500;
Δ = b2-4ac
Δ = 02-4·20·(-500)
Δ = 40000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{40000}=200$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-200}{2*20}=\frac{-200}{40}
=-5
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+200}{2*20}=\frac{200}{40}
=5
$