20w2-11w=3

Solution for 20w2-11w=3 equation:

20w^2-11w=3

We move all terms to the left:

20w^2-11w-(3)=0

a = 20; b = -11; c = -3;
Δ = b2-4ac
Δ = -112-4·20·(-3)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-19}{2*20}=\frac{-8}{40}
=-1/5
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+19}{2*20}=\frac{30}{40}
=3/4
$