20t-8(t+2)=-28

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Solution for 20t-8(t+2)=-28 equation: 



20t-8(t+2)=-28

We move all terms to the left:

20t-8(t+2)-(-28)=0

We add all the numbers together, and all the variables

20t-8(t+2)+28=0

We multiply parentheses

20t-8t-16+28=0

We add all the numbers together, and all the variables

12t+12=0

We move all terms containing t to the left, all other terms to the right

12t=-12

t=-12/12

t=-1

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