20f+(-12f-15)=3(4f+5)

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Solution for 20f+(-12f-15)=3(4f+5) equation: 



20f+(-12f-15)=3(4f+5)

We move all terms to the left:

20f+(-12f-15)-(3(4f+5))=0

We get rid of parentheses

20f-12f-(3(4f+5))-15=0



We calculate terms in parentheses: -(3(4f+5)), so:

3(4f+5)

We multiply parentheses

12f+15

Back to the equation:

-(12f+15)



We add all the numbers together, and all the variables

8f-(12f+15)-15=0

We get rid of parentheses

8f-12f-15-15=0

We add all the numbers together, and all the variables

-4f-30=0

We move all terms containing f to the left, all other terms to the right

-4f=30

f=30/-4

f=-7+1/2

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