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20=9+3(s-7)
We move all terms to the left:
20-(9+3(s-7))=0
We calculate terms in parentheses: -(9+3(s-7)), so:We get rid of parentheses
9+3(s-7)
determiningTheFunctionDomain 3(s-7)+9
We multiply parentheses
3s-21+9
We add all the numbers together, and all the variables
3s-12
Back to the equation:
-(3s-12)
-3s+12+20=0
We add all the numbers together, and all the variables
-3s+32=0
We move all terms containing s to the left, all other terms to the right
-3s=-32
s=-32/-3
s=10+2/3
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