20=8(y+3)-4(2y+1)

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Solution for 20=8(y+3)-4(2y+1) equation: 


Simplifying
20 = 8(y + 3) + -4(2y + 1)

Reorder the terms:
20 = 8(3 + y) + -4(2y + 1)
20 = (3 * 8 + y * 8) + -4(2y + 1)
20 = (24 + 8y) + -4(2y + 1)

Reorder the terms:
20 = 24 + 8y + -4(1 + 2y)
20 = 24 + 8y + (1 * -4 + 2y * -4)
20 = 24 + 8y + (-4 + -8y)

Reorder the terms:
20 = 24 + -4 + 8y + -8y

Combine like terms: 24 + -4 = 20
20 = 20 + 8y + -8y

Combine like terms: 8y + -8y = 0
20 = 20 + 0
20 = 20

Add '-20' to each side of the equation.
20 + -20 = 20 + -20

Combine like terms: 20 + -20 = 0
0 = 20 + -20

Combine like terms: 20 + -20 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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