20=7(y-5)+4y

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Solution for 20=7(y-5)+4y equation: 



20=7(y-5)+4y

We move all terms to the left:

20-(7(y-5)+4y)=0



We calculate terms in parentheses: -(7(y-5)+4y), so:

7(y-5)+4y

We add all the numbers together, and all the variables

4y+7(y-5)

We multiply parentheses

4y+7y-35

We add all the numbers together, and all the variables

11y-35

Back to the equation:

-(11y-35)



We get rid of parentheses

-11y+35+20=0

We add all the numbers together, and all the variables

-11y+55=0

We move all terms containing y to the left, all other terms to the right

-11y=-55

y=-55/-11

y=+5

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