20=5/9(f-32

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Solution for 20=5/9(f-32 equation: 



20=5/9(f-32

We move all terms to the left:

20-(5/9(f-32)=0



Domain of the equation: 9(f-32)+20!=0

We move all terms containing f to the left, all other terms to the right

9(f-32)!=-20

f∈R



We multiply all the terms by the denominator


-(5=0

We add all the numbers together, and all the variables

=0

f=0/1

f=0

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