20=5(b+2)+b

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Solution for 20=5(b+2)+b equation: 



20=5(b+2)+b

We move all terms to the left:

20-(5(b+2)+b)=0



We calculate terms in parentheses: -(5(b+2)+b), so:

5(b+2)+b

We add all the numbers together, and all the variables

b+5(b+2)

We multiply parentheses

b+5b+10

We add all the numbers together, and all the variables

6b+10

Back to the equation:

-(6b+10)



We get rid of parentheses

-6b-10+20=0

We add all the numbers together, and all the variables

-6b+10=0

We move all terms containing b to the left, all other terms to the right

-6b=-10

b=-10/-6

b=1+2/3

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