20=4x+6(2x-10)

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Solution for 20=4x+6(2x-10) equation: 



20=4x+6(2x-10)

We move all terms to the left:

20-(4x+6(2x-10))=0



We calculate terms in parentheses: -(4x+6(2x-10)), so:

4x+6(2x-10)

We multiply parentheses

4x+12x-60

We add all the numbers together, and all the variables

16x-60

Back to the equation:

-(16x-60)



We get rid of parentheses

-16x+60+20=0

We add all the numbers together, and all the variables

-16x+80=0

We move all terms containing x to the left, all other terms to the right

-16x=-80

x=-80/-16

x=+5

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