20=4(n-2)+3n

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Solution for 20=4(n-2)+3n equation: 



20=4(n-2)+3n

We move all terms to the left:

20-(4(n-2)+3n)=0



We calculate terms in parentheses: -(4(n-2)+3n), so:

4(n-2)+3n

We add all the numbers together, and all the variables

3n+4(n-2)

We multiply parentheses

3n+4n-8

We add all the numbers together, and all the variables

7n-8

Back to the equation:

-(7n-8)



We get rid of parentheses

-7n+8+20=0

We add all the numbers together, and all the variables

-7n+28=0

We move all terms containing n to the left, all other terms to the right

-7n=-28

n=-28/-7

n=+4

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