20=4(c+2)

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Solution for 20=4(c+2) equation: 



20=4(c+2)

We move all terms to the left:

20-(4(c+2))=0



We calculate terms in parentheses: -(4(c+2)), so:

4(c+2)

We multiply parentheses

4c+8

Back to the equation:

-(4c+8)



We get rid of parentheses

-4c-8+20=0

We add all the numbers together, and all the variables

-4c+12=0

We move all terms containing c to the left, all other terms to the right

-4c=-12

c=-12/-4

c=+3

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