20=4(4x+2)-20

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Solution for 20=4(4x+2)-20 equation: 



20=4(4x+2)-20

We move all terms to the left:

20-(4(4x+2)-20)=0



We calculate terms in parentheses: -(4(4x+2)-20), so:

4(4x+2)-20

We multiply parentheses

16x+8-20

We add all the numbers together, and all the variables

16x-12

Back to the equation:

-(16x-12)



We get rid of parentheses

-16x+12+20=0

We add all the numbers together, and all the variables

-16x+32=0

We move all terms containing x to the left, all other terms to the right

-16x=-32

x=-32/-16

x=+2

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