20=3x-2(3x+1)-5

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Solution for 20=3x-2(3x+1)-5 equation: 



20=3x-2(3x+1)-5

We move all terms to the left:

20-(3x-2(3x+1)-5)=0



We calculate terms in parentheses: -(3x-2(3x+1)-5), so:

3x-2(3x+1)-5

We multiply parentheses

3x-6x-2-5

We add all the numbers together, and all the variables

-3x-7

Back to the equation:

-(-3x-7)



We get rid of parentheses

3x+7+20=0

We add all the numbers together, and all the variables

3x+27=0

We move all terms containing x to the left, all other terms to the right

3x=-27

x=-27/3

x=-9

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