20=3/2(2x+4)+4x

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Solution for 20=3/2(2x+4)+4x equation: 



20=3/2(2x+4)+4x

We move all terms to the left:

20-(3/2(2x+4)+4x)=0



Domain of the equation: 2(2x+4)+4x)!=0

x∈R



We multiply all the terms by the denominator


-(3+20*2(2x+4)+4x)=0



We calculate terms in parentheses: -(3+20*2(2x+4)+4x), so:

3+20*2(2x+4)+4x

determiningTheFunctionDomain
20*2(2x+4)+4x+3

We add all the numbers together, and all the variables

4x+20*2(2x+4)+3

Wy multiply elements

4x+40x(2+3

Back to the equation:

-(4x+40x(2+3)



We add all the numbers together, and all the variables

-(4x+40x5=0

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