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20=3-5(1x+1)
We move all terms to the left:
20-(3-5(1x+1))=0
We add all the numbers together, and all the variables
-(3-5(x+1))+20=0
We calculate terms in parentheses: -(3-5(x+1)), so:We get rid of parentheses
3-5(x+1)
determiningTheFunctionDomain -5(x+1)+3
We multiply parentheses
-5x-5+3
We add all the numbers together, and all the variables
-5x-2
Back to the equation:
-(-5x-2)
5x+2+20=0
We add all the numbers together, and all the variables
5x+22=0
We move all terms containing x to the left, all other terms to the right
5x=-22
x=-22/5
x=-4+2/5
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