20=3-(c+5)

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Solution for 20=3-(c+5) equation: 



20=3-(c+5)

We move all terms to the left:

20-(3-(c+5))=0



We calculate terms in parentheses: -(3-(c+5)), so:

3-(c+5)

determiningTheFunctionDomain
-(c+5)+3

We get rid of parentheses

-c-5+3

We add all the numbers together, and all the variables

-1c-2

Back to the equation:

-(-1c-2)



We get rid of parentheses

1c+2+20=0

We add all the numbers together, and all the variables

c+22=0

We move all terms containing c to the left, all other terms to the right

c=-22

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