20=3+6(d-4)

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Solution for 20=3+6(d-4) equation: 



20=3+6(d-4)

We move all terms to the left:

20-(3+6(d-4))=0



We calculate terms in parentheses: -(3+6(d-4)), so:

3+6(d-4)

determiningTheFunctionDomain
6(d-4)+3

We multiply parentheses

6d-24+3

We add all the numbers together, and all the variables

6d-21

Back to the equation:

-(6d-21)



We get rid of parentheses

-6d+21+20=0

We add all the numbers together, and all the variables

-6d+41=0

We move all terms containing d to the left, all other terms to the right

-6d=-41

d=-41/-6

d=6+5/6

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