20=3(n-5)

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Solution for 20=3(n-5) equation: 



20=3(n-5)

We move all terms to the left:

20-(3(n-5))=0



We calculate terms in parentheses: -(3(n-5)), so:

3(n-5)

We multiply parentheses

3n-15

Back to the equation:

-(3n-15)



We get rid of parentheses

-3n+15+20=0

We add all the numbers together, and all the variables

-3n+35=0

We move all terms containing n to the left, all other terms to the right

-3n=-35

n=-35/-3

n=11+2/3

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