20=2-(b+10)

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Solution for 20=2-(b+10) equation: 



20=2-(b+10)

We move all terms to the left:

20-(2-(b+10))=0



We calculate terms in parentheses: -(2-(b+10)), so:

2-(b+10)

determiningTheFunctionDomain
-(b+10)+2

We get rid of parentheses

-b-10+2

We add all the numbers together, and all the variables

-1b-8

Back to the equation:

-(-1b-8)



We get rid of parentheses

1b+8+20=0

We add all the numbers together, and all the variables

b+28=0

We move all terms containing b to the left, all other terms to the right

b=-28

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