20=2(k+3)

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Solution for 20=2(k+3) equation: 



20=2(k+3)

We move all terms to the left:

20-(2(k+3))=0



We calculate terms in parentheses: -(2(k+3)), so:

2(k+3)

We multiply parentheses

2k+6

Back to the equation:

-(2k+6)



We get rid of parentheses

-2k-6+20=0

We add all the numbers together, and all the variables

-2k+14=0

We move all terms containing k to the left, all other terms to the right

-2k=-14

k=-14/-2

k=+7

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