20=2(j+3)

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Solution for 20=2(j+3) equation: 



20=2(j+3)

We move all terms to the left:

20-(2(j+3))=0



We calculate terms in parentheses: -(2(j+3)), so:

2(j+3)

We multiply parentheses

2j+6

Back to the equation:

-(2j+6)



We get rid of parentheses

-2j-6+20=0

We add all the numbers together, and all the variables

-2j+14=0

We move all terms containing j to the left, all other terms to the right

-2j=-14

j=-14/-2

j=+7

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