20=2(d+3)

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Solution for 20=2(d+3) equation: 



20=2(d+3)

We move all terms to the left:

20-(2(d+3))=0



We calculate terms in parentheses: -(2(d+3)), so:

2(d+3)

We multiply parentheses

2d+6

Back to the equation:

-(2d+6)



We get rid of parentheses

-2d-6+20=0

We add all the numbers together, and all the variables

-2d+14=0

We move all terms containing d to the left, all other terms to the right

-2d=-14

d=-14/-2

d=+7

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