20=2(7+3q)

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Solution for 20=2(7+3q) equation: 



20=2(7+3q)

We move all terms to the left:

20-(2(7+3q))=0

We add all the numbers together, and all the variables

-(2(3q+7))+20=0



We calculate terms in parentheses: -(2(3q+7)), so:

2(3q+7)

We multiply parentheses

6q+14

Back to the equation:

-(6q+14)



We get rid of parentheses

-6q-14+20=0

We add all the numbers together, and all the variables

-6q+6=0

We move all terms containing q to the left, all other terms to the right

-6q=-6

q=-6/-6

q=1

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