20=2(24-m)+3(m-4)

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Solution for 20=2(24-m)+3(m-4) equation: 



20=2(24-m)+3(m-4)

We move all terms to the left:

20-(2(24-m)+3(m-4))=0

We add all the numbers together, and all the variables

-(2(-1m+24)+3(m-4))+20=0



We calculate terms in parentheses: -(2(-1m+24)+3(m-4)), so:

2(-1m+24)+3(m-4)

We multiply parentheses

-2m+3m+48-12

We add all the numbers together, and all the variables

m+36

Back to the equation:

-(m+36)



We get rid of parentheses

-m-36+20=0

We add all the numbers together, and all the variables

-1m-16=0

We move all terms containing m to the left, all other terms to the right

-m=16

m=16/-1

m=-16

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