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20=15+2x(-3x+4)
We move all terms to the left:
20-(15+2x(-3x+4))=0
We calculate terms in parentheses: -(15+2x(-3x+4)), so:We get rid of parentheses
15+2x(-3x+4)
determiningTheFunctionDomain 2x(-3x+4)+15
We multiply parentheses
-6x^2+8x+15
Back to the equation:
-(-6x^2+8x+15)
6x^2-8x-15+20=0
We add all the numbers together, and all the variables
6x^2-8x+5=0
a = 6; b = -8; c = +5;
Δ = b2-4ac
Δ = -82-4·6·5
Δ = -56
Delta is less than zero, so there is no solution for the equation
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