20=-30+3/2(t)

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Solution for 20=-30+3/2(t) equation: 



20=-30+3/2(t)

We move all terms to the left:

20-(-30+3/2(t))=0



Domain of the equation: 2t)!=0

t!=0/1

t!=0

t∈R



We add all the numbers together, and all the variables

-(3/2t-30)+20=0

We get rid of parentheses

-3/2t+30+20=0

We multiply all the terms by the denominator


30*2t+20*2t-3=0

Wy multiply elements

60t+40t-3=0

We add all the numbers together, and all the variables

100t-3=0

We move all terms containing t to the left, all other terms to the right

100t=3

t=3/100

t=3/100

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